I don't know if it is a good idea to post this, but I just feel like

doing this.

First of all, you have to know the gravity of all the planets, the

moon, and the sun. I only know that the gravity of the moon is 1/6 g,

which is a sixth of the gravity of earth.

First, let me derive an equation.

V(vertical final) = V(vertical initial) - gt

g = gravitational acceleration t = time

Since the vertical velocity is zero at the top of the trajectory of a

baseball hit by somebody, and I am only talking about half the

trajectory:

V(vertical initial) = gt

I want to know the time the ball takes until it reaches the ground:

t = 2 (V(vertical initial))/g

I want to know the horizontal distance the ball takes on our planet.

Horizontal Distance =HD = V(horizontal initial) times time

= 2(V(horizontal initial) V(vertical initial))/g

Now let's assume that Howard Johnson can swing a bat on

any heavenly body so that the initial horizontal velocity and the

initial vertical velocity of the ball hit by him are always the same

as those of a 430 foot homerun he hit a few months ago at Shea Stadium

On the moon, the gravity is a sixth of that of our planet. So:

HD(on the moon) = 2(V(horizontal initial) V(vertical initial)) / (g/6)

=6 (2(V(horizontal initial) V(vertical initial))) / g

= 6 (HD(on earth)) = 6 times 430 feet = 2580 feet

Wow! Easily a new record.

Since I forgot the gravitational acceleration of each planet and the

sun, this is all I can do.

The easiest way to know this is to know that the distance a guy can

hit the ball is inversely proportional to the gravity of the place,

assuming that there is no air friction.

Since I am in hurry, I have to go without double-checking. I think

this is right since I am a physics major.